There were 6 men. Each man carried 6 bags. Each bag had 6 cats. Each cat had 6 kittens. How many legs in all?
2006-12-19 16:00:54 · 3 answers · asked by mhiaa 7 in Science & Mathematics ➔ Mathematics
6 men * 2 legs/man = 12 human legs
6 men * 6 bags/man * 6 cats/bag = 216 cats
216 cats * 4 cat legs/cat = 864 cat legs
216 cats * 6 kittens/cat * 4 kitten legs/kitten = 5184 kitten legs
Total = 12 + 864 + 5184 = 6060 legs.
Another way of looking at it: Each bag has 6 cats and 36 kittens (6 per cat) for a total of 42 animals or 168 legs. There are 36 bags so 168*36 = 6048. Add the 12 human legs and you have 6060.
James, you only forgot that each man has 6 bags so there are 36 bags in total.
2006-12-20 02:45:06 · answer #1 · answered by Anonymous · 0⤊ 0⤋
6*2 + ((6*4)*6 + 6*4)*6 = 1020
six men have 12 legs
each cat has 6 kittens, 6 kittens have 6*4 = 24 legs
there are 6 cats, so the legs of the kittens are 6*24 = 144
one bag has 6 cat and 6 kitten, thus one bag has : 6*4 + 6*6*4 = 168 legs
6 bag have 6 * 168 = 1008 legs
total 12 + 1008 = 1020
2006-12-20 10:41:30 · answer #2 · answered by James Chan 4 · 0⤊ 2⤋
180
6 times 2=12
6bagswith 6 cats=24
6bags with6 kittens 24 times 6=144
12+24+144=180
2006-12-20 10:39:42 · answer #3 · answered by Dave aka Spider Monkey 7 · 0⤊ 2⤋