2006-12-19 15:45:46 · 9 answers · asked by car 1 in Science & Mathematics ➔ Mathematics
on my paper it says: Solve the following system of equations: {y=2x+3
{y=2x-3
2006-12-19 15:53:31 · update #1
There is no solution. Note that if y=2x+3 and y=2x-3, then 2x+3 = 2x-3, which implies that 3=-3, which is false. The graph of these functions is two parallel lines, which being parallel, do not intersect.
2006-12-19 15:49:04 · answer #1 · answered by Pascal 7 · 0⤊ 0⤋
for these two equations to both be true then
2x+3=y=2x-3
subtracting 2x from each we get
3=y-2X=-3
or
3=-3
thus these two equations can not simultaneously be true.
another way to arrive at the same conclusion is through graphs of the two equations
The graph of each of the equations is a straight line with slope of 2
The line representing the first equation crosses the Y axis at Y=3
The line representing the second equation crosses the Y axis at Y=-3
Since the lines have the same slope and cross the Y axis at different points they are parallel and not coincident.
Since the lines never cross there is no one solution true for both equations.
2006-12-20 01:11:43 · answer #2 · answered by anonimous 6 · 0⤊ 0⤋
Observe, each equation is in slope-intercept form. For each equation the slope is 2. The lines are parallel because the slopes are equal. Parallel lines have no common points, as such, there is no solution.
Graphing: The first line contains the point (0,3). A second point is
(-1, 1). The second line crosses the y-axis at (0, -3) and a second point is (1, -1).
2006-12-20 01:27:25 · answer #3 · answered by S. B. 6 · 0⤊ 0⤋
2x-3=2x+3
2x=2x+0
0x=0
There is no solution. If you graphed these on paper or in the graphing calculator, the graphs do not intersect. They are parallel from each other.
2006-12-20 12:56:54 · answer #4 · answered by Anonymous · 0⤊ 0⤋
These equations are called "inconsistent," meaning (as others have said) that they do not have a common solution. When graphed, they form two parallel lines (which, of course, do not intersect, so there are no common points).
2006-12-19 23:56:58 · answer #5 · answered by actuator 5 · 0⤊ 0⤋
there are no possible solutions for these equations. this can be verified by drawing a graph for the two lines. they will not intersect because they are parallel lines. Hence no solution.
2006-12-19 23:50:10 · answer #6 · answered by Titan 4 · 0⤊ 0⤋
AS Y/X GIVES THE SLOPE
FOR THIS EQNS
SLOPE FOR BOTH LINES ARE SAME
I.E. Y/X=2.
WHICH SHOWS THESE LINES ARE PARALLEL
AND THEY CAN'T MEET.
2006-12-20 09:41:48 · answer #7 · answered by cham 2 · 0⤊ 0⤋
y=2x+3...1
y=2x-3.....2
adding 1&2
2y=4x
y=2x........3
subtracting
0=6
absurd
2006-12-20 13:34:16 · answer #8 · answered by openpsychy 6 · 0⤊ 0⤋
No solution .....
2006-12-20 01:42:44 · answer #9 · answered by Srinivas c 2 · 0⤊ 0⤋