do you think either of the williams sisters will ever get back to the top of the game?
2006-12-19 14:39:14 · 8 answers · asked by chick douglas 3 in Sports ➔ Tennis
NO!
They are just like Andy Roddick.
Just try to ""power" their way to a win.
It worked for awhile until people started to figure out how to use their power against them.
There time in the sun is over.
2006-12-20 15:49:16 · answer #1 · answered by Ohms 2 · 0⤊ 0⤋
I think it is possible that Serena and Venus can get back to the top but I don't think they will ever be #1 again. I think they may win 1 or 2 majors but not be consistent enough to be #1. They seem to have loss some of the drive that they once had that has made them one of the best players in the world. I also think that they have too many injury problems and by getting older, they will continue to get injury's. I don't think they can go 6 months without getting the injury bug. So, i think it is possible, but i don't think its going to happen, especially because i think they have too many injuries.
2006-12-19 22:44:31 · answer #2 · answered by someon09 2 · 0⤊ 0⤋
I think Serena still has it in her, but times have changed and they cannot go out and play 8-10 tournaments a year and expect to still win Grand Slams. Of course, if they get back 100% into tennis commitment, then of course, they could both win some Slams again.
2006-12-20 05:57:12 · answer #3 · answered by Bored With This 4 · 0⤊ 0⤋
Doubtful. I don't think they want to. Even if they did get the fire back, they have several players who can go toe to toe with them.
2006-12-20 15:18:20 · answer #4 · answered by nymetsking 3 · 0⤊ 0⤋
probably not. If one of them did it would be Venus. They have made plenty of money anyway!
2006-12-19 23:24:53 · answer #5 · answered by Lightbulb without a cause! 2 · 0⤊ 0⤋
no they had their time
2006-12-20 01:41:26 · answer #6 · answered by john 7 · 0⤊ 0⤋
They can overcome anything..I believe so
2006-12-20 23:26:00 · answer #7 · answered by Anonymous · 0⤊ 0⤋
No!
2006-12-21 18:18:42 · answer #8 · answered by Bo V 4 · 0⤊ 0⤋