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i have to graph this and im not sure how. can someone explain?

x+y<(or=) 6
x-y<(or=) 4
x>0
y>0

2006-12-19 14:09:23 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

first you must convert it to y=mx+b form. for now, the
x+y<(or=) 6 also equals y=-x+6 graph that.

x-y<(or=) 4 also equals y=x-4 graph that.

then comes the shading. to shade, plug in a set of variables (i suggest 0,0) in to each equation. if the statement is true, shade to the side in which your variables are set. (e.g. if y< or =x-4, then 0< or =0-4. since this statement is false, you would shade to the side that does not contain the point 0,0.

does this make any sense to you?

2006-12-19 14:17:15 · answer #1 · answered by Alex 1 · 0 0

Solve the first two for y and get:

y <= 6- x
y >= -4+x

Graph those and if it is >, shade above. If it is <, shade below.

Then, shade above y = 0 and to the right of x = 0.

Make any sense? You need more?

2006-12-19 22:14:13 · answer #2 · answered by Mike J 3 · 0 0

if you go to www.quickmath.com, click Plot under Inequalities, then click on Advanced, then type in

x + y <= 6
x - y <= 4
x > 0
y > 0

It should like like a quadrilateral

2006-12-19 22:26:43 · answer #3 · answered by Sherman81 6 · 0 0

aren't you being taught in school? are you attending class, doing homework? don't you have a classbook?

2006-12-19 22:12:41 · answer #4 · answered by Rick 5 · 0 0

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