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i know that absAx +By +c/sqrtA^2 + B^2 is the distance formula from a point to a line. but could someone give me an example of how to plug the points in?

2006-12-19 14:04:35 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

if you have a line represented by the equation Ax + By + c = 0 and a point with coordinates (X, Y), then plug the numbers into the formula. Example 2X + 3Y - 5 = 0 and point (-1, 9). The distance is (2*(-1) + 3*9 - 5) / sqrt(4 + 9) = 20 / sqrt(13) = 5.55

2006-12-19 14:16:13 · answer #1 · answered by Rick 5 · 0 0

you're surprisingly much suited. You a approach or the different stored a detrimental interior the unconventional. you could have SQRT(109). of direction distance does not contain complicated numbers or negatives. so which you knew something became amiss. artwork each little thing interior the unconventional first: -3-0 = -3 (-3)^2 = 9 -9-a million = -10 (-10)^2 = one hundred leaves you with: SQRT(9+one hundred) SQRT(109) is approximately 10 which "feels" suited once you think approximately the standards 9 and a million. you could additionally draw a triangle and visualize it that way. This equation is largely taken from the pythagorean theorem. additionally, FYI, "radical" is the logo ? which skill to take the muse of a type.

2016-12-18 16:24:23 · answer #2 · answered by Erika 4 · 0 0

The Distance Formula
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www.purplemath.com/modules/distform.ht...
Distance Formula
The advantage of the Distance Formula is that you do not need to draw a picture ... The Distance Formula is really just a...
regentsprep.org/Regents/math/distance/...
Practice with Distance Formula
Math A. Working with. Distance (Length) Answer the following questions pertaining to. distance (length) and coordinate ......
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2006-12-19 15:53:42 · answer #3 · answered by Byzantino 7 · 2 0

I believe, and it's been a while here, that you solve your linear equation for 0. Then x's coefficient is A, y's coefficient is B, and c's what's leftover. (x,y) comes from the point itself.

2006-12-19 14:10:38 · answer #4 · answered by J G 4 · 0 0

That's a really hard way to put the distance formula. Try this one instead.

__________________ <---- Square root sign
| (x1*x2)^2+(y1*y2)^2

2006-12-19 14:12:38 · answer #5 · answered by Answer 2 · 0 0

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