if you had -(3wz^4)(-5w^2z^3)
how would you do that?
would you distribute the negative sign to the 3wz^4 or to the 3, then w, then z?
after that, could you multiply the two parts in parenthesis in colums?
2006-12-19 13:33:23 · 5 answers · asked by *~SAMI~* 2 in Science & Mathematics ➔ Mathematics
the negative sign would only go with the coefficient (3) as in -3wz^4. If there was an addition/subtraction sign you would distribute the negative to all of the coefficients ex: -(3x+5) is the same as -3x-5. The answer to your example would be 15w^3z^7.
2006-12-19 13:38:26 · answer #1 · answered by Zack 2 · 2⤊ 0⤋
Here's the first step:
(-3wz^4)(-5w^2z^3)
Multiply like terms:
15w^3z^7
2006-12-19 13:38:34 · answer #2 · answered by Anonymous · 1⤊ 0⤋
you would distribute it to the 3, but then if you multiplied the -3 by the other numbers, they would all be negative, anyway, unless one of them equaled -something
2006-12-19 14:04:34 · answer #3 · answered by rissa.rocks 2 · 1⤊ 0⤋
The two negatives give you a positive; now just do the work
15(w^3)(z^7)
2006-12-19 13:38:30 · answer #4 · answered by kellenraid 6 · 2⤊ 0⤋
-ve*-ve=+ve
so 15w^3z^7
2006-12-19 13:36:31 · answer #5 · answered by raj 7 · 4⤊ 1⤋