question in statistics?

Question

what is the probability of getting 3 heads in tossing a coin 4 times?

Answer 1

There are 16 possibilities (2 possibilities raised to the fourth power for four tosses).

Each possibilitiy is equally likely.

Four possibilities lead to your scenario:
HHHT
HHTH
HTHH
THHH

So the probability is 4 out of 16 or 0.25

Another way to do this is to use the binomial distribution charts:
p = 0.5
n = 4
successes = 3

And look up the probability.

Answer 2

Although it is modeled as a binomial the answer depends on p, the probability of getting a head in one toss.

What if it's a 2 headed coin? Or an unbalanced coin? Huh, all you smarty-pants?

Assuming that you know p, the success probability for one toss,

then P( 3 heads in 4 tosses) = 4C3*p^3(1-p)

There's symmetry so that 4C3 = 4C1 = 4

Note that this is the 4 ways that you can get the one tail!

Answer 3

This is a binomial experiement with p = .5 (asusming the coin is fair), n = 4, and k = 3. The probability for a given outcome in a binomial experiment is C(n,k)(p^k)(q^(n-k)) which is
C(4,3)(.5^3)(.5^1) =
4 x 1/8 x 1/2 = 4 / 16 = 1/4 or ,25

Answer 4

i think that it may be(0.25)

Answer 5

0.25