Factoring polynomials help?

Question

What are the steps to factoring a polynomial when a is greater than one?


ex. 2m^2 - 11m + 15

Answer 1

Here's some checks of proof ( Click back then go on http://www.uutx.com to get started)

Answer 2

I got a really cool trick for this, but it's hard to write it here, limitations with the graphics and so forth. Let me try and write it out and get back with you...

Make a 4 by four box with positions for four numbers in it, like this:
|,,,,,,,, ,,,,,,,,,,|
|........ ..........|

In the top row, put the factors of the first term, that is, factors of 2m^2. the only possiblities are 1 and 2, so put those.
| 2 1|
| ... ... |
In the bottom row, put the factors of the last term, that is, 15. Here's where you have to work in the signs. Since 15 is positive, they both have to be the same sign, either both + or both -, since - x - = + and also + x + = +. Since 5 x 3 = -5 x -3 = 15, put -5 and -3 in the bottom row.
[ 2 1 |
|-5 -3 |
Now multiply down the diagonals, add the results, and hopefully you shouold get the middle number. here, (2 x -3) + (1 x -5) = -11, which is the middle number.
Finally, read the coefficients fom the columns
(2x - 5)(1x -3)
Now, suppose you had put the -5 and -3 in the bottom row in the opposite order? Then they wouldn't add up to -11 (try it!) and you'd know that you need to rearrange them. that's why I recommend doing this with a pencil rather than a pen. So there's still a certain amount of trial and error involved but not near as much as before.

Answer 3

hey, I actually learned this a few days ago!

2m^2-11m+15

2m^2-11m+15 -you have to multiply the a andc terms so that's 30m.

2m^2-6m-5m+15 -factor with the number you get from above step (-6m-5m=30m, -6m-5m= -11m

2m^2-6m -5m+15 - treat these two as seperate equations

2m(m-3) -5(m-3) -take out the GCF and the equation in parenthesis is the same ALWAYS.

(2m-5)(m-3) -take the equation not in parenthesis and take the equation in parenthesis.

Answer 4

The problem to solve is:

2m^2 - 11m + 15


Multiply the exponent of m by 2giving


Ok, this goes here...


This isn't part of the answer...just my own internal thinking....

Multiply and 2

Multiply and 1



This isn't part of the answer...just my own internal thinking....
The just gets copied along.

Let's see, ummmm...




Let's see, ummmm...

Multiply m and 11

Multiply m and 1



The m just gets copied along.

Let's see, ummmm...
m
m


This isn't part of the answer...just my own internal thinking....
11m

Ok, this goes here...


Wait...I'm thinking....


Wait...I'm thinking....



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The final answer is

is a valid trinomial that might be factorable.
This trinomial can be factored. Here is it in factored form:
=( m-3 )( 2m-5 )

Answer 5

2m^2 - 11m + 15

I always like using the quadratic formula

m = (-b ± sqrt(b^2 - 4ac))/(2a)

m = (-(-11) ± sqrt((-11)^2 - 4(2)(15)))/(2(2))
m = (11 ± sqrt(121 - 120))/4
m = (11 ± sqrt(1))/4
m = (11 ± 1)/4
m = (12/4) or (10/4)
m = 3 or (5/2)

ANS : (2x - 5)(x - 3)

Answer 6

Hey, Hey now, little lady. What you do with the polynomials in the privacy of your own home is your business, I don't wanna see that **** when I'm walking down the street. Just kidding, I love your avatar, you're so cute.

Answer 7

first you look for common terms. there are none. so the answer is.....(2m+5)(2m-3)

Answer 8

5 factorial example:

5! = 5x4x3x2x1

Answer 9

http://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/col_alg_tut7_factor.htm