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I really need help on Balancing Equations. i dont get it at all... Can anyone help me.. please?

2006-12-19 13:23:19 · 7 answers · asked by Anonymous in Science & Mathematics Chemistry

7 answers

Count up and write down the number of each type of atom on each side of the equation.

Pick an atom and balance it by placing a coefficient in front of the molecule that contains the unbalanced atom.

Continue until all atoms are balanced.
Generally it is best to do H and O last if water, H2 or O2 are in the equations.

Eg.

C6H12O6 + O2 -----> CO2 + H2O
Reactants side
6C
12H
8O
Products side
1C
2H
3O

Balance C first by placing a 6 in front of CO2 - note that this changes the amt of O on the left
C6H12O6 + O2 -----> 6CO2 + H2O
Reactants side
6C
12H
8O
Products side
6C
2H
12O

Next balance H by placing a 6 in front of H2O - this also change amt O on the left
C6H12O6 + O2 -----> 6CO2 + 6H2O
Reactants side
6C
12H
8O
Products side
6C
12H
18O

Finally balance O by placing a 6 in front of the O2
C6H12O6 + 6O2 -----> 6CO2 + 6H2O
Reactants side
6C
12H
18O
Products side
6C
12H
18O

2006-12-19 13:36:21 · answer #1 · answered by champagne0684 2 · 0 0

Basically you can add coefficients to any molecule in the chemical equation and then everything in that molecule get multiplied by that number. The goal is to have the smallest coefficients possible and still have the same number of each element on both sides.

ex.

Unbalanced:
C6H14 + O2 ==> H2O + CO2
C=6 + H=14 + O=2 ==> C =1+ H=2+ O=3

Balanced but the coefficients aren't fully reduced:
4C6H14 + 38O2 ==> 28H2O + 24CO2
C=24 + H=56 + O=76 ==> C=24 + H=56 + O=76

Can be reduced by a factor of 2

Balanced:
2C6H14 + 19O2 ==> 14H2O + 12CO2
C=12 + H=28 + O=38 ==> C=12 + H=28 + O=38

2006-12-19 21:40:56 · answer #2 · answered by Ross P 3 · 0 0

I'm learning that right now too.......this might take a while
When you start, make sure your states of matter are written (solid, liquid, gas, aqueous). Write a "scoreboard" of how many of each element you have.
Example: HCl - H2 + Cl2 1 H 1 Cl - 2H 2Cl
Start with your most difficult combo first, like if you have an odd number on one side and an even number on the other side.
Sometimes plugging just one number in can balance everything.
If that didn't help you, I"m sorry! Search on Google for a website to help you. Good luck!

2006-12-19 21:29:55 · answer #3 · answered by Short and sweet 3 · 0 1

Sure. what equation. Secondly the simple rule is all the no. of Atom of each element in the reactants must equal the product. If 2 O in reactants than there must be 2 reactants in the products

2006-12-19 21:35:27 · answer #4 · answered by raveen_cs83 2 · 0 0

Can you give me some equations that you have difficulty balancing and I can help you with it?

2006-12-19 21:27:19 · answer #5 · answered by ispakles 3 · 0 1

on wat equation
like H2 + O2--> H2O you balance it like 2H2 + O2--> 2H2O

2006-12-19 21:35:13 · answer #6 · answered by lindi 2 · 0 0

yes wat u need help wid???

2006-12-19 21:24:40 · answer #7 · answered by Anonymous · 0 1

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