Factor the polynomial. 47^2 - 81?

Answer 1

= 47^2 - 9^2
= (47+9)(47-9)
= 56 * 38

if you meant (4x^2-81) then = (2x+9)(2x-9)

Answer 2

47^2 - 81 is not a polynomial since there are no variables. But if you want to factor the expression, you have
x^2 - y^2 = (x - y) * (x + y), i.e.,

(47 - 9) * (47 + 9)

Answer 3

this is not a polynomial... you NEED an x!! at least!

47^2 - 81 = (47-9) (47+9) = (38)(56) .

Answer 4

Since both of the numbers are perfect squares, and the second is being subtracted from the first, you can use the method of factoring called difference of 2 perfect squares. It factors into (x^2-9)(x^2+9). The first binomial can still be factored into (x-3)(x+3), but the second binomial is a prime polynomial. So, your answer is (x-3)(x+3)(x^2+9).

Answer 5

That's a difference of two squares, although there's no letters in it to make it look like one. Whenever you see a square subtracted from another square, factor it like this. First put pairs of parenthesis with a + in one and a - in the other::
( + )( - )
Next put the roots of each square in each spot.
(47+9)(47-9)
There ya go...
Note -- there is some leeway in here since multplication and addition are communitave. But it's best to choose one pattern and stick with it, even if someone else does it a little different, that way you won't make mistakes.

Answer 6

(47-9)(47+9)=(38)(56)

Answer 7

2128 =

Answer 8

2128