Please solve (sin(x) * cos (x))/(1-cos^2 (x)) (x is not raised to the power)
2006-12-19 12:59:15 · 9 answers · asked by DadinTrouble 1 in Science & Mathematics ➔ Mathematics
(sin(x) * cos(x))/(1 - cos(x)^2)
(sin(x)cos(x))/(sin(x)^2)
(cos(x))/(sin(x))
cot(x)
ANS : cot(x)
2006-12-19 14:03:56 · answer #1 · answered by Sherman81 6 · 0⤊ 0⤋
(1-cos^2(x)) = sin^2(x)
so you cancel one with the sin(x) from the numerator and the answer is
(cos(x))/(sin(x))= Ctg(x)
2006-12-19 13:02:52 · answer #2 · answered by oposites2 2 · 0⤊ 0⤋
sinx cosx /1-cos^2x
= sinx cosx/1-cos^2x
= sinx cos x/sin^2x
= cos x/ sin x
= cot x
2006-12-19 21:17:24 · answer #3 · answered by george t 2 · 0⤊ 0⤋
(sin x)(cos x)/(sin^2 x) <-----sin^2x + cos^2x = 1
= cos x / sin x
= cot x
2006-12-19 13:01:16 · answer #4 · answered by keely_66 3 · 0⤊ 0⤋
sin^2(x) + cos^2(x) = 1
so
sin(x)*cos(x)/sin^2(x) = cos(x)/sin(x) then you finish the last part
2006-12-19 13:06:03 · answer #5 · answered by Mr.Math 1 · 0⤊ 0⤋
(sin(x) * cos (x))/(1-cos^2 (x))
(sinx)(cosx)/(sin^2(x))
cosx/sinx
cotx
2006-12-19 13:01:33 · answer #6 · answered by Anonymous · 0⤊ 0⤋
cscx/(a million+cscx)=(a million-sinx)/cos^2 x)? LHS = (a million/sinx)/[(a million+a million/sinx)] Multiplying through sinx/sinx, we get, LHS = a million/(a million+sinx) Multiplying through (a million-sinx)/(a million-sinx), we get, LHS = (a million-sinx)/[(a million+sinx)*(a million-sinx)] = (a million-sinx)/(a million-sin^2x) = (a million-sinx)/(cos^2x) = RHS
2016-12-15 04:37:14 · answer #7 · answered by karsten 4 · 0⤊ 0⤋
sinxcosx/sin^2x
=cosx/sinx=cotx
2006-12-19 13:04:12 · answer #8 · answered by raj 7 · 0⤊ 0⤋
cot(x)
2006-12-19 13:03:09 · answer #9 · answered by Alex M 2 · 0⤊ 0⤋