Unit Circle?

Question

I need to find the trigonometric functions for x being 0 and y being -1

Answer 1

If x = 0 and y = -1, then you're pointing straight down along the y-axis. This would be an angle of 3 pi/2 radians or 270 degrees (plus or minus any integral number of rotations). Call that angle Q, since I'm too lazy to type it out multiple times, in which case

sin Q = -1

cos Q = 0

tan Q = sin Q/cos Q = undefined

csc Q = -1

sec Q = undefined

cot Q = 0

I hope that's what you're looking for.

Answer 2

That is 3 pi / 2 or 270 degrees.

On a unit circle, cosine is x and sine is y. So the sine is -1 and cosine is 0.

Tangent is sine/cosine or y/x or here -1/0 which is undefined.

Answer 3

in degrees and exact values

sin 0 = 0
sin 30 = square root of 1/2
sin 45 = square root of 2 divided by 2
sin 60 = square root of 3 divided by 2
sin 90 = 1

cos 0 = 1
cos 30 = square root of 3 divided by 2
cos 45 = square root of 2 divided by 2
cos 60 = 1/2
cos 90 = 0

tan 0 = 0
tan 30 = square root of 3 divided by 3
tan 40 = 1
tan 60 = square root of 3
tan 90 = undefined

csc 0 = undefined
csc 30 = 2
csc 45 = square root of 2
csc 60 = 2 times the square root of 3 divided by 3
csc 90 = 1

sec 0 = 1
sec 30 = 2 times the square root of 3
sec 45 = square root of 2
sec 60 = 2
sec 90 = undefined

cot 0 = undefined
cot 30 = square root of 3
cot 45 = 1
cot 60 = square root of 3 divided by 3
cot 90 = 0

Answer 4

cos x = 0
sin x = -1
tan x is undefined
sec x is undefined
csc x = -1
cot x = 0