i need to simplify by dividing (x^3 + 2x^2 + 3x - 6)/(x - 1)?

Answer 1

(x^3 + 2x^2 + 3x - 6)/(x - 1) = (x-1) (x^2+3x+6)/(x-1) = x^2+3x+6 .

Answer 2

1 2 3 -6
0 1 3 6
1 3 6
so when you divide the quotient is
x^2+3x+6

Answer 3

(x^3 + 2x^2 + 3x - 6)/(x - 1) = (x-1) (x^2+3x+6)/(x-1) = x^2+3x+6
:D

Answer 4

You have to understand that explaining long division with Yahoo Answers is an extremely difficult task.

All I can say is that you'd first consider the first terms (x and x^3), and ask yourself, "How many times does x go into x^3?" Your answer would be x^2, you would write an x^2 on top of the division divider, and multiply x^2 to each of (x - 1), subtract like you would long division and you get a new polynomial.

You would repeat this process until you have a remainder and a quotient.

Sorry I couldn't be much help but I hope it's at least a start.

Answer 5

a million. 5 2.forty 8 3. 947>5x-2 4. 904 5. a million-2/4 6.7x(fifty seven*2)/4 7. 80 5 8. comparable as #2 9. y=4n basically Kidding, Iv'e been out of faculty for 21 years, i did no longer like homework and exams then and that i surely do no longer wanna do them now. lol amazing attempt nonetheless! good success

Answer 6

. . . x^2. +. 3x. +. 6
. . . -----------------------
x - 1)x^3 + 2x^2 + 3x - 6
. . . . x^3. -. x^2
. . . .-------------
. . . . . . . . 3x^2 + 3x
. . . . . . . . 3x^2. - 3x
. . . . . . . . .---------------
. . . . . . . . . . . . .. 6x - 6
. . . . . . . . . . . . .. 6x - 6
. . . . . . . . . . . . . .-------
. . . . . . . . . . . . . . . . . 0

Answer 7

(x³ + 2x² + 3x - 6)/(x - 1)

x - 1) x + 2x² + 3x - 6(x²
........ x³ . - x² .... ↓.↓
........ --------- .... ↓.↓
............... 3x² + 3x .... (3x
............... 3x². - 3x. ↓
............... ---------- . ↓
............ ........... 6x - 6 (6
............ ........... 6x - 6
............ ........... -------
............ .............. ... 0
............ ........... -------

So (x³ + 2x² + 3x - 6)/(x - 1) = x² + 3x + 6