1. 0.05 molar sulphuric acid, H2SO4 solution 2. 0.44g sodium hydroxide NaOH in 250cm3 solution
2006-12-19 10:12:04 · 4 answers · asked by raytunz 1 in Science & Mathematics ➔ Earth Sciences & Geology
it is 6.3856 megatrons
2006-12-19 10:13:22 · answer #1 · answered by Dave 2 · 1⤊ 2⤋
0.05M of H2SO4
the molar of H+ : 0.05 * 2 = 0.1M
pH = - log[H+] = 1
0.44g sodium hydroxide NaOH in 250cm3 solution
the moles of NaOH : 0.44 / 40 = 0.011
the molar of NaOH : 0.011 / 0.25 = 0.044
the molar of OH- : 0.044
pOH = -log[OH-] = 1.357
pH = 14 - pOH = 12.643
2006-12-19 18:26:54 · answer #2 · answered by James Chan 4 · 1⤊ 0⤋
the answer can be calculated using the following equations
pH= - log (Molarity)
and
Molarity = Moles Acid ion/Litres
Moles = (grams sample)/(gram Molecular Weight)
1. pH= - log (.05)
2. pH= -log ((.44g/40g per Mole)/.250L)
I'll leave you to the calculator work
2006-12-19 18:24:26 · answer #3 · answered by piercesk1 4 · 1⤊ 0⤋
no idea - its looks to my limited brain like acid, acid, alkali, alkali
so first two between ph1-6 and the second two ph 8-14
wheres my universal indicator?
2006-12-19 18:27:25 · answer #4 · answered by olivier1uk 3 · 0⤊ 1⤋