2006-12-19 09:47:37 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
What is there to prove?
2006-12-19 09:51:22 · answer #1 · answered by knock knock 3 · 0⤊ 1⤋
If you want to CONSTRUCT the complex numbers, let C={(x,y):x,y are real}. Define (x,y)+(a,b)=(x+a,y+b) and (x,y)*(a,b)=(xy-ab,xa+ya). Then the 'real numbers' are those of the form (x,0) and we identify x with (x,0). Note that (0,1)*(0,1)=(-1,0), so we can let i=(0,1). Then every complex number is of the form a+b*i and the usual rules can be easily shown.
2006-12-19 10:13:46 · answer #2 · answered by mathematician 7 · 2⤊ 0⤋
i wager those are absolute cost signs and indications? nicely if |Z1|=|Z2|=a million, then both Z1 and Z2 equivalent ±a million. (±a million)²=±a million, because one would nicely be helpful and one would nicely be detrimental, besides the indisputable fact that the numerical cost continues to be the same. and considering you're proving that |Z1*Z2|=a million, the negativity or positivity would not count number because it turns into helpful no count number what.
2016-11-30 23:35:09 · answer #3 · answered by rieck 4 · 0⤊ 0⤋
You can't prove something that is imaginary. Mathematicians just made them up to help as part of the toolkit to solve problems.
2006-12-19 09:53:15 · answer #4 · answered by Anonymous · 0⤊ 3⤋
What is your question?
2006-12-19 09:56:23 · answer #5 · answered by 1,1,2,3,3,4, 5,5,6,6,6, 8,8,8,10 6 · 0⤊ 1⤋
Please state what you want to prove!
2006-12-19 10:14:04 · answer #6 · answered by steiner1745 7 · 0⤊ 0⤋