I asked yesterday, but the answer still doesn't match. So I'm hoping there is a math whiz out there that will be able to help!!
I tried the calculus websites and calculator, but I have no clue on how to get the answer.
The questions is to find the derivative for y=(cosx)^x, where -pi/2 < x < pi/2.
The answer is (cosx)^(x-1) (cosx ln(cosx) - xsin x))
Please help! and thank you.
If done normally, the answer is dy=(cosx)^x[ln(cosx)-xtanx]
However, I'm guessing that the restriction on x, which is (-pi/2 < x < pi/2) is what makes the answer different. Much help appreciated to the person who can figure it out! ^^
2006-12-19
08:53:27
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2 answers
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asked by
mewmew_buzz
2
in
Education & Reference
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