2006-12-19 08:47:16 · 11 answers · asked by hans d 1 in Science & Mathematics ➔ Mathematics
It's not a parabola but a circle. General form of a circle is (x-h)^2+(y-k)^2=r^2. (h,k) is the center of the circle and r is the radius. In this case, center is (0,0) with radius sqrt(3).
2006-12-19 08:49:57 · answer #1 · answered by knock knock 3 · 0⤊ 0⤋
This is most certainly NOT a parabola, and I can explain why.
Algbraically, parabolas are characterized by one variable being a power of 2, and the other variable being to the first power. Therefore,
y = ax^2 + bx + c, for some constants a, b, and c, is a parabola, as well as
x = ay^2 + by + c
In the first case, we have a parabola opening either up or down, and in the latter case, we have a parabola opening sideways.
x^2 + y^2 = 3 is not a parabola; it is a circle with radius equal to the square root of 3, or sqrt(3), and the center located at (0,0).
2006-12-19 08:55:27 · answer #2 · answered by Puggy 7 · 0⤊ 0⤋
Is this a parabola???Graph the equation x^2+y^2=3...?
No, it is not a parabola. It is a circle with center at origin and radius = sqrt(3).
I'm not sure what the three dots between the 3 and the question mark mean.
2006-12-19 08:53:25 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
element: x^2 + x - a million when you consider that this equation does not element gently, you will would desire to apply the Quadratic formula to discover the fee(s) of x. look at your equation like this: ax^2 + bx - c meaning: a = a million b = a million c = -a million Plug it into the Quadratic formula: x = (-b +or- squarerootof(b^2 - 4(a)(c)) / (2a) x = (-a million +or- sqrt((a million)^2 - 4(a million)(-a million)) / 2 x = (-a million +or- sqrt(a million - -4)) / 2 x = (-a million +or- sqrt(5)) / 2 ^when you consider which you may no longer take the sq. root of 5 (it comes out as a decimal), it is so a procedures as you may take it. in basic terms element left to do is chop up the + or - through making 2 equations to that end, x = (-a million + sqrt(5)) / 2 AND x = (-a million - sqrt(5)) / 2 or x = .sixty two x = -a million.sixty two after plugging in all of the above x values returned into the equation (plugging .sixty two and -a million.sixty two into the unique equation, attempting to discover one which will make the equation equivalent 0), you will discover that the two solutions paintings. x = -a million.sixty two and .sixty two
2016-12-15 04:26:54 · answer #4 · answered by Anonymous · 0⤊ 0⤋
No. It's a circle with center at the orgin 7 radius √3
2006-12-19 08:53:20 · answer #5 · answered by yupchagee 7 · 0⤊ 0⤋
No, it's a circle with center at the origin and a radius of sq. rt. 3
2006-12-19 08:49:08 · answer #6 · answered by MateoFalcone 4 · 0⤊ 0⤋
x^2+y^2=3 is a circle with center in (0,0) and with radius = root(3).
Th
2006-12-19 09:11:10 · answer #7 · answered by Thermo 6 · 0⤊ 0⤋
no its a circle with a radius of the square root of 3 and center of (0,0)
2006-12-19 08:49:47 · answer #8 · answered by d.treadway 2 · 0⤊ 0⤋
This is the equation for an ellipse.
2006-12-19 08:59:23 · answer #9 · answered by steve_geo1 7 · 0⤊ 0⤋
No, it is a circle.
2006-12-19 08:58:08 · answer #10 · answered by Anonymous · 0⤊ 0⤋