identify the two acids in the following reaction. explain your answer.
2006-12-19 07:41:22 · 5 answers · asked by lamide e 1 in Science & Mathematics ➔ Chemistry
Anything that loses a proton going from right to left or left to right in the equation is an acid.
So CH3COOH and H2O are the acids.
2006-12-19 07:45:14 · answer #1 · answered by Gervald F 7 · 0⤊ 0⤋
Ok, the acids are CH3COOH and H2O. Why? Okay, the -COOH ending on anything means that it is a weak organic acid. Also, if you look at NaOH, the OH designates a base, so the other must be an acid. Normally, you wouldn't think of water as an acid or base, because its neutral.. but only most of the times. So, the CH3 and CO2 (from COOH) is released into the atmosphere after the rxn and the OH and the leftover H+ from the -COOH bond to form H2O. So, the Na+ is oxidized (normally just Na), which leaves it a base, and the H2O is reduced (from H+) to make it an acid.
2006-12-19 07:49:33 · answer #2 · answered by Anonymous · 0⤊ 0⤋
The first acid is acetic acid, CH3COOH. NaOH is a base.
One defintion of an acid, is that an acid is a donor of H+. Thus Na+ cannot be an acid.
H2O undergoes dissociation to produce: H+ and OH-. Thus, H2O may be considered to be acidic because it is a donor of H+.
2006-12-19 07:48:26 · answer #3 · answered by Yellow Tail 3 · 0⤊ 0⤋
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2016-12-30 16:07:43 · answer #4 · answered by mccloy 3 · 0⤊ 0⤋
In this reaction there is only one acid: CH3COOH........
But the reaction is not correct....where did you get it from?
2006-12-19 07:55:55 · answer #5 · answered by Dana 1 · 0⤊ 0⤋