can you balance the equation C2H6 + O6 ----> CO2 + H2O???????

Answer 1

6C2H6 + 7O6 ----> 12CO2 + 18H2O

1. C2H6 + O6 ----> "2"CO2 + H2O
2. C2H6 + O6 ----> 2CO2 + "3"H2O
3. C2H6 + "7/6"O6 ----> 2CO2 + "3"H2O
4. "6"C2H6 + "7"O6 ----> "12"CO2 + "18"H2O

Answer 2

I think there is a mistake in this equation because the oxygen need to be write in his molecular form an this is bimolecular (O2) in the reactants side, this reaction is a typic combustion or an organic compound that produce CO2 and water.

C2H6 + O2 --> CO2 + H2O

C2H6 + 7/2*O2 --> 2CO2 + 3H2O

2C2H6 + 7O2 --> 4CO2 + 6H2O

(4C, 12H, 14O)

If oxygen really are write like that in this equation, i suposse need a charge, other element next to it or something like that.

But answering your question like is:

C2H6 + O6 --> CO2 + H2O

if we multiply by 2 the CO2 for equilibrate C we have:

C2H6 + O6 --> 2CO2 + H2O

now for equilibrate H if we multiply H2O by 3 we have:

C2H6 + O6 --> 2CO2 + 3H2O

so there are 6 H and 2 C

now the oxygen in left side are 6 and in right side are 7
the only form to equilibrate this is multiplying the left side oxygen by 7/6

C2H6 + 7/6*O6 --> 2CO2 + 3H2O

so we have finally in both sides:
2 C, 6 H, 6 O

if we want to have "complete" elements and not fractional
we may multiply by 6 all the equation:

6*(C2H6 + 7/6*O6 --> 2CO2 + 3H2O)

obtainig:
6C2H6 + 7O6 --> 12CO2 + 18H2O

Answer 3

Here is the balance equation for the equation above:

12C2H6 + 14O6 ----> 24CO2 + 36 H2O

but I think this equation is a combustion reaction and it is suppose to be like this:

C2H6 + O2 ------> CO2 + H2O + ENERGY

if it is that then this is the balance equation:

2C2H6 + 7O2 ----> 4CO2 + 6H2O + ENERGY

Answer 4

-06 to both sides then simplify then u -CO2 to both sides and simplify

Answer 5

C2H6 + 2O6 --------- 2CO2 + 3H2O + O5