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If two identical objects slide down slopes of different steepness, will their normal reaction force still be equal?

2006-12-19 06:35:36 · 5 answers · asked by Iwy 2 in Science & Mathematics Physics

5 answers

No, the normal force will vary by the angle of the slope by the cosine.

where N=m*g*cos(a)
where a is the angle of the slope with respect to horizontal.

j

2006-12-19 06:44:49 · answer #1 · answered by odu83 7 · 0 0

No. The normal reaction force is the component of the object's weight that the slope supports.

(Yes, it equals mgcos a, where m = mass of object in kilograms; g = 9.8 to convert your mass unit on earth to its weight force in newtons; and a = the acute angle the slope makes with the horizontal.)

As angle a gets closer to a rt angle, the slope supports less and less of the object's weight; i.e. the object is supported less and less by the slope. At perpendicular the object's weight is no longer supported by the slope, and all the object's weight is directed parallel to the slope; your normal reactive force would be zero.

2006-12-19 10:20:16 · answer #2 · answered by answerING 6 · 0 0

No, they are not. The Normal force will depend on the angle of the steepness.

2006-12-19 06:45:49 · answer #3 · answered by Cu Den 2 · 1 0

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2016-12-15 04:22:04 · answer #4 · answered by Anonymous · 0 0

no because normal reaction depends on the angle of the slope.normal reaction is directly proportional to tan theta(-), where theta is the value of the slope in degrees.

2006-12-19 06:53:31 · answer #5 · answered by Anonymous · 0 0

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