Solve sin x = 0, when 0≤ x ≤ 360˚? What quadrant is it in?

Question

Solve sin x = 0, when 0≤ x ≤ 360˚? What quadrant is it in?

Answer 1

Solve sin x = 0, when 0≤ x ≤ 360˚? What quadrant is it in?

sin x = 0 0˚ ≤ x ≤ 360˚

So x = 0˚, 180˚, 360˚ (x lies on the boundaries of quadrants 4 and 1 and quadrants 2 and 3)

Since 0 = ±0

Then sin 360˚ = sin (360˚ ± 0˚) = ± sin 0˚ = ±0 = 0

Sin 180˚ = sin (180˚ ± 0˚) = ± sin 0˚ = ±0 = 0

ie on the boundary can be dealt with as in either quadrant

Answer 2

In fact sin x = 0 implies that
x = 0, +/- 180, +/- 360 and so on.
all these values don't lie in any quadrant because the either lie between the first and fourth quadrants or between the second and third ones. Some people used to call the angles which are multiples of 90 degrees as a quadrant angles. because they are at the boundary of these quadrants,

Answer 3

sinx=0
sin 0=0 , sin 180*=0 and sin 360=0
so if sin x=0
then x=0 or pi or 2 pi if 0<=x<=360
x=0 Q1
x=180* Q2
x=360* Q1 again

Answer 4

x lies on the Ox axis and x belongs to the set {0, pi}.
x can be either 0, either pi, because:

sin 0 = sin pi=0.

Answer 5

Sin(x) goes to zero at multiples of π.....0, π, 2π, 3π, 4π, etc.

Quadrant? Good question....it lies on the x-axis in between the first and fouth and the second and third. So I don't know how to answer that. Doesn't sound like a good question to me.

Answer 6

0 and 360 degrees.

cos = x
sin = y

at 0degrees and 360degrees, the coordinates are (1,0)

at 180degrees, the coordinates are (-1 , 0)

Answer 7

sin2x=0.8193 discover out the attitude whose sin is 0.8193 equate it to 2x discover x by technique of dividing by technique of two which will dive one answer for the different answer subtract the first answer from one hundred and eighty*