Multiplying Algebriac Fractions?

Question

-4b2/X * 2x5/B The answer is -8Bx4


The #2 and #5 are exponents just incase someone wondered.
Could someone spell this out for me? =)

Answer 1

When exponents are in fractions, the upper ones cancel out the lower ones. In your case, the B squared (B*B) becomes a single B and cancels out the lower one. The X to the fifth (X*X*X*X*X) becomes X to the fourth and cancels out the lower one. Leaving you with your answer. If it helps you, expand the exponents like I did and cross out the common ones from the top and bottom (B2/B = (B*B)/B = B/1 = B).

Answer 2

When you multiple fractions, you only need to multiple the numerators and multiple the denominators.
When exponents are involved, all the exponents algebraically when multiplying and subtract them when dividing.
So you have:
-4 * 2 = -8
B^2 / B = B^(2-1) = B^1 = B
x^5 / x = x^(5-1) = x^4
Putting it all together, you get
-8 * B * x^4

Answer 3

-4b^2 2x^5
------- * -------
x b

(-4)(b^2)(2)(x^5)
-----------------------
xb
Since you have the commutative and associative laws for multiplication, you can change the order
(-4)(2)(b^2)(x^5)
---------------- This is the same as
bx
-8 b^2 x^5
-------------- now you have to know how to do b^2/b and x^5/x.
bx


b is really b^1 and x is x^1. When dividing you subtract the exponents. b^2/b^1 = b^(2-1) or b^1 or b. x^5/x^1 = x^(5-1) or x^4.
Another way to look at it is that the fraction above is really
-8*b*b*x*x*x*x*x
---------------------
b*x
You can "cross out" (because you are dividing numerator and denominator by the same number) one "x" in top and bottom, and one "b" in top and bottom. This leaves -8bx^4

Answer 4

(In my notation, X^5 would mean that 5 is the exponent of X. Also, I will write out the times sign each time just for clarification.)

First you multiply the numerator and denominator to get -8*B^2*X^5/B*X. Then you start cancelling the variables. Think of it as this: -8*B*B*X*X*X*X*X/B*X. Therefore, you can cancel out one X and one B out of the numerator and the denominator to get -8*B*X*X*X*X, which is the same as -8*B*X^4.

Answer 5

(-4b^2 / x ) * ( 2x^5 / b ) Multiply the top ( numerators ) and then multiply the bottom (denominators)
- 8 b^2 x^5 /x b , now simplify by moving small exponents to big.

-8 b x^4 is the answer

Answer 6

(-4B^2/x)(2x^5/B)
Multiply the numerators together getting -8B^2x^5 =Bx(-8Bx^4)
Multiply the denominators together getting Bx
Now divide numerator by denominator getting -8Bx^4
The Bx terms cancel out.

Answer 7

first b=B, I think, and x=X
(-4b^2)/x * 2(x^5)/b = -8 bx^4 just cancel out factors. You must be more careful in your writing.