I have a math test tomorrow, and I need help with certain math material in order to pass this test?

Question

solve these inequalities:
1) 3p-6>21=
2) 9h+2<-79
3) -9h-6+12h+40=22
4) 3p-16<20
5) j/4-8<4

ok for #4 the only anwers that I have is
a= p<-12
b=p<1/3
c=p<-48
d=p< 1 1/3

sorry # 4 did have an answer of p<12, I wrote the wrong answer choice for letter c,
thank you all so much. for those of you who like to do these equations, I ahve a few more that you all can help me with.

Answer 1

1) 3p-6>21

3p > 27
p > 9

2) 9h+2<-79

9h < -81
h < -9

3) -9h-6+12h+40=22

3h -34 = 22
3h = 56
h = 18 2/3

4) 3p-16<20

3p < 36
p < 12

5) j/4-8<4

j/4 < 12
j < 48

Answer 2

1)
3p - 6+6 > 21+6

3p/3 > 27 /3

p > 9

2)
9h + 2 - 2< -79- 2

=> 9h/9 < -81/9

=> h < -9

3)
-9h -6 + 12h + 40 = 22
Rearrage:
(-9h + 12h) + (- 6 + 40) = 22
=> 3h + 34 - 34 = 22 -34

=> 3h/3 =-12/3

=> h = -4

4)
3p -16 +16 < 20+16

=> 3p/3 < 36/3

=> p < 12

5)
j/4 - 4+4 < 4+4

=> j/4 < 8 => 4*(j/4) < 8 * 4
=> j < 32

Answer 3

First you want to change the inequalities to equalities and then solve for the variable. I have done so with step-wise procedures so you can see how it works.

1) 3p - 6 > 21
add 6 to both sides, combine like terms: 3p - 6 + 6 > 21 + 6
3p > 27
divide both sides by 3: 3p/3 > 27/3
p > 9

2) 9h + 2 < -79
subtract 2 from both sides: 9h + 2 - 2 < -79 - 2
9h < -81
divide both sides by 9: 9h/9 < -81/9
h < -9

3) -9h - 6 + 12h + 40 = 22
combine like terms: 3h + 34 = 22
subtract 34 from both sides: 3h + 34 - 34 = 22 - 34
3h = -12
divide both sides by 3: 3h/3 = -12/3
h = -4

4) 3p - 16 < 20
add 16 to both sides: 3p - 16 + 16 < 20 + 16
3p < 36
divide both sides by 3: 3p/3 < 36/3
p < 12

5) j/4 - 8 < 4
add 8 to both sides: j/4 - 8 + 8 < 4 + 8
j/4 < 12
multiply both sides by 4: j/4 * 4 < 12 * 4
j < 48

Hope that helps explain the method.

Answer 4

1. First: add 6 to both sides:

3p - 6 + 6 > 21 + 6
3p > 27

Second: set "p" by itself on one side > divide both sides by 3:

3p/3 > 27/3
p > 9

2. First: subtract 2 from both sides:

9h + 2 - 2 < -79 - 2
9h < -81

Second: divide both sides by 9:

9h/9 < -81/9
h < -9

3. First: combine "like" terms:

-9h + 12h - 6 + 40 = 22
3h + 34 = 22

Second: subtract 34 from both sides:

3h + 34 - 34 = 22 - 34
3h = -12

Third: divide both sides by 3:

3h/3 = -12/3
h = - 4

4. try it-look at one and two for reference.

5. First: get rid of the fraction > take the denominator and multiply it by everything:

4(j/4) - 4(8) < 4(4)
j - 32 < 16

Second: add 32 to both sides:

j - 32 + 32 < 16 + 32
j < 48

Answer 5

3p-6>21
3p>21+6
3p>27 p>7 pE(7,+ infint)
9h+2<-79 9h>-81 h>-9 hE[-9,+infinit)
-9h-6+12h+40=22
-9h+12h=22+6-40 3h=-12 h=-4
3p-16<20 3p<26 p<26/3 pE(- infint,26/3)
j/4-8<4 j/4<12 j<48 jE(48,+infinit)

Answer 6

1) 3p-6>21
adding 6
=3p>27
dividing by 3
p>9
2) 9h+2<-79
adding -2
9h<-81
dividing by 9
h<-9
or flipping the inequalitysugn
-h>9
3) -9h-6+12h+40=22
simplifying 3h+34=22
adding -34
3h=-12
dividing by 3
h=-4
4) 3p-16<20
adding 16
3p<36
dividing by 3
p<12
5) j/4-8<4
adding 8
j/4<12
multiplying by 4
j<48

Answer 7

u need to solve for the constant:

for the first one

3p-6 > 21
so 3p > 21 + 6
3p > 27
p > 9

second
9h+2 < -79
9h < -79 - 2
9h < -81
h < -9

try solving the others if u still need help
email me at [e-mail]

Answer 8

1) p > 9
2) h < -9
3) h = -4
4) p < 12
5) j < 3

Answer 9

1) p > 9
2) h >-9
3)h= -4
4) p < 12
5) j < 48

Answer 10

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