i need help with this chemistry question about moles.?

Question

plzz helpme with the mole to mole conversion stuff plz help.

13.If 4:39 mol of ethane (C2H6) undergo combus-
tion according to the unbalanced equation
C2H6 + O2 = CO2 + H2O;
how much oxygen is required? Answer in
units of mol.


14. How much CO2 is formed? Answer in units of
mol. from the question above


15. How much H2O is formed? Answer in units of
mol. from the number 13.


work and answers would be very helpful thanks.

Answer 1

First balancing the equation we get

2C2H6 + 7 O2 --> 4 CO2 + 6 H2O

This means 2 molecules of Ethane reacts with 7 molecules of oxygen to give 4 molecules of Carbon Di Oxide and 6 moleclues of water.

In other words 2 moles of ethane reacts with 7 moles of oxygen to give 4 moles of carbon di oxide and 6 moles of water.

If we take 4.39 moles of ethane then it should react with
(7/2)*4.39 moles of oxygen which is 15.365 moles of oxygen
(4/2)*4.39 moles of CO2 which is 8.78 moles of CO2
(6/2)*4.39 moles of water which is 13.17 moles of H2O.

Answer 2

specific, i will furnish help to shop face, whether that's in basic terms a caricature face. you % fifty 8 mL of a nil.4M answer: (0.4 mol solute) / (a million L sol'n) x fifty 8 mL x (a million L) / (one thousand mL) This final term is a conversion element. i take advantage of them plenty. If a million L = one thousand mL [by ability of definition] then a million = (a million L) / (one thousand mL) and you would be able to multiply any quantity by ability of a million without changing it. Cancel out the instruments and you will desire to be left with moles of solute. You did no longer % the molecular weight to sparkling up the priority, yet measuring out a mole of aluminum sulphate is dicey company and not utilising a sturdy mole-o-meter, so maximum chemists convert moles to grams: ??? mol solute x (342 g solute) / (a million mol solute) [the molecular weight you calculated; i did no longer verify, even though it style of feels existence like] = ??? g solute What you have been searching for?

Answer 3

2C2H6 + 7O2 ===> 4CO2 + 6H2O

4.39molC2H6 x 7molO2/2molC2H6 = 4.39*7/2 = 15.4molO2

mol C2H6 cancel out leaving mol O2. The 7/2 factor comes from the balanced equation. Similarly:

4.39molC2H6 x 4molCO2/2molC2H6 = molCO2

4.39molC2H6 x 6molH2O/2molC2H6 = molH2O