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2006-12-19 00:52:55 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

It's like the NHL, they try and they try but they cannot stop it from continuing

2006-12-19 00:54:44 · answer #1 · answered by Distressed homeowner 2 · 1 0

Infinite series that converge are very useful and can be used to obtain certain values to any degree of accuracy desired.

Some examples:
sin x = x- x^3/3! +x^5/5 - .... +(-1)^(n+1)[(x^(2n-1))/(2n-1)!] + .....
cosx = 1- x^2/2! + x^4/4! - ...+(-1)^(n+1)[(x^(2n-2))/(2n-2)!] + ...
e^x = 1+x +x^2/2!+x^3/3! +x^4/4! +.... x^n/n! + ......
pi/4 = 1-1/3+1/5-1/7+1/9- 1/11 +..........

The harmonic series 1+1/2 +1/3+1/4 +1/5 +...1/n ...
is divergent and if continued forever will grow infinitely large.

The geometric series 1+r+r^2 +r^3 +....r^n +.....
is convergent if |r|<1; otherwise it is divergent. If |r| < 1, the series will converge to the value 1/(1-r)

2006-12-19 10:14:05 · answer #2 · answered by ironduke8159 7 · 0 0

Series may be finite, or infinite; in the first case they may be handled with elementary algebra, but infinite series require tools from mathematical analysis if they are to be applied in anything more than a tentative way.

The sum of an infinite series a0 + a1 + a2 + ... is the limit of the sequence of partial sums

read more --> http://en.wikipedia.org/wiki/Series_(mathematics)

2006-12-19 08:56:01 · answer #3 · answered by DanE 7 · 0 0

the series w/o the An th term is known as infinite series.

infinite series may or may not have a limit.

if it has the limit then the sum can be calculated by the formula:
s= a1/(1-r)

2006-12-19 09:19:53 · answer #4 · answered by Anonymous · 0 0

Learn to use a search engine. Then you can find thousands of websites about infinite series, convergence, divergence, and all manner of good stuff.


Doug

2006-12-19 09:35:16 · answer #5 · answered by doug_donaghue 7 · 0 1

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