2006-12-18 23:56:57 · 6 answers · asked by sam 2 in Computers & Internet ➔ Hardware ➔ Add-ons
PCI-E cards require PCI-E slots...u wil know them cos they are longer than normal PCI slots and always situated above the normal ones. and there is a MASSIVE bandwidth increase from AGP. which in english means that the graphics card has alot more pipeline to recieve data from the processor, so it goes faster. PCI-E is the future my friend and its also getting pretty cheap...
2006-12-19 00:04:38 · answer #1 · answered by darklordkain 3 · 1⤊ 0⤋
Nope, Sorry. there is 3 different slot variety video enjoying cards AGP - PCI - PCI-e (convey) one million: you may sell the cardboard and purchase a PCI-e card 2: touch the corporation which you gained the video card from ask ask if there's a thank you to commerce the cardboard. 3: touch the corporation who made the video card and ask if there's a thank you to commerce the cardboard for a PCi-e card be conscious: Assuming you have not opened the container.........
2016-12-30 15:41:39 · answer #2 · answered by valaria 4 · 0⤊ 0⤋
Yes, PCI-express graphics cards are faster then AGP video cards, but no you cannot insert one into a PCI slot they would not work or fit.
Here's a pic.. http://www.ackadia.com/computer/images/pci_express_proto_mobo.jpg
2006-12-19 00:03:12 · answer #3 · answered by Fremen 6 · 0⤊ 0⤋
A PCI-Express slot is different than a PCI slot. PCI-E is better tha AGP. For comparison of the throughput speeds
PCI 2.2 = 133mb/sec
AGP 1.0 = 266mb/sec
AGP 2x = 533 mb/sec
AGP 4x = 1.06gb/sec
AGP 8x = 2.1 gb/sec
PCI express with its sixteen pairs carries 4GB/s as opposed to AGP 8X 2.1 GB/s.
2006-12-19 00:22:49 · answer #4 · answered by Sunny 4 · 1⤊ 0⤋
No it doesnt need anything extra. And you want to know if its better than AGP? AGP is an advanced graphics port and is used pretty much only for a graphics card.
2006-12-19 00:09:11 · answer #5 · answered by xI Crusader lx 2 · 0⤊ 0⤋
No it can't and yes, it is better than A\GP.
2006-12-18 23:59:38 · answer #6 · answered by Booooo 2 · 1⤊ 0⤋