2006-12-18 23:31:13 · 13 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Combine like terms:
17x-5=17x-5
It's an infinite solution because both sides of the equation contains the same numbers or values.
2006-12-19 01:19:02 · answer #1 · answered by Anonymous · 4⤊ 0⤋
Hey I can help you solve any question no matter what the numbers in it. Rule 1: What ever you do to one side you can do to the other side of the equation. Rule 2: Add or subtract so that you get all the "x's" on one side of the equation. Rule 3: Whatever is on the otherside = x. So (1) Add up the x's on the left hand side of the equation. i.e. 8x + 9x is 17x so then you have: 17x -5 = 17x -5 Now get the x's on one side of the equation and the numbers on the other side. So I"ll add 5 to both sides of the equation: 17x - 5 + 5 = 17x-5 + 5 and then simplify (i.e. -5+5=0) so: 17x = 17x Dividing both sides by 17 ( i.e. 17x/17 = x) Hence 17x/17 =17x/17 and simplifying: x = x There is no solution as far as I can see hence answer I would have done is D. You really should spend the time to work through this solution. Otherwise you will fail your school maths course. You need to do this everyday maths stuff for simple things (i.e. paying off a home loan so you can calculate stuff - in the end it comes down to making $$ so if you wanna buy cool clothes or drive a fast car I really recommend you sit down and work through this stuff or ask a grown up to explain the reasoning to you so EVERY QUESTION BECOMES EASY!
2016-05-23 06:56:04 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Well you have 17x on both sides so the whole problem is negligible...as in no variable to solve for!
8x+9x-5=17x-5
17x-5=17x-5
Both sides of the eqn are the same!
2006-12-18 23:33:22 · answer #3 · answered by kowalley 5 · 0⤊ 0⤋
8x-5 + 9x = 17 x -5
8x + 9x - 17x = -5 + 5
0 x = 0
x = 0/0
x = 0
2006-12-22 19:42:47 · answer #4 · answered by mozac 2 · 0⤊ 0⤋
8x - 5 + 9x = 17x - 5
Add the x's on left hand side
17x - 5 = 17x - 5
A balanced equation, therefore by definition all values of x are valid where x is either a positive integer, a negative integer or zero. Except infinity, because a multiple of infinity cannot be expressed in Euclidian Mathematics, therefore if infinity were to be used in the solution it would have to be defined, possibly as a domain such as infinity is defined as being greater or equal to such and such....
2006-12-19 02:26:46 · answer #5 · answered by Gaz 5 · 0⤊ 0⤋
8x -5 +9x= 17x -5
add 8x+ 9x on the left: 17x -5= 17x -5
so x can be anything
2006-12-18 23:41:15 · answer #6 · answered by Just me 5 · 0⤊ 0⤋
8x-5 + 9x = 17x - 5
17x - 5 = 17x - 5
child's play it is..but can't imagine why u ask this problem
2006-12-18 23:39:54 · answer #7 · answered by Blue P 4 · 0⤊ 0⤋
8x-5+9x=17x-5
You add 8 and 9 together ('cause they both have x variables)=
17x-5=17x-5
The two 5 cancel each other out=
17x=17x
And you can put any number in the x place. :-)
2006-12-18 23:50:04 · answer #8 · answered by auf wiedersehen 2 · 0⤊ 0⤋
17x - 17 x = -5 + 5
0x = 0
0 = 0
2006-12-19 03:25:26 · answer #9 · answered by Speed Demon - Public Servant 5 · 0⤊ 0⤋
8x + 9x - 17x = 5 - 5
0x = 0
L = R
Answer: all real numbers.
x can be anything, and the equation is allways true!
2006-12-18 23:33:52 · answer #10 · answered by Anonymous · 2⤊ 0⤋