2006-12-18 23:29:01 · 25 answers · asked by colin050659 6 in Entertainment & Music ➔ Movies
My usual rate is 10k plus expenses.
Cheers.
2006-12-19 01:39:57 · answer #1 · answered by chopchubes 4 · 0⤊ 0⤋
It would depend, I mean if they were a horrible person, they abused children or worse, then maybe $1500. If they were just a bad person, but not terrible maybe $2500. I wouldn't do it if they were a good person and someone just wanted to get rid of them for insurance or custody reasons.
But I don't think I would like Prison so I would never actually kill anyone.
2006-12-19 11:21:59 · answer #2 · answered by voidtillnow 5 · 0⤊ 0⤋
$100 Billion
2006-12-19 07:30:41 · answer #3 · answered by Dr Dee 7 · 0⤊ 0⤋
How much would I pay to have someone bumped off ?!- there is plenty of mad Junkies in Glasgow who would do it for a Tenner bag of Smack..a Kebab and 6 cans of Special Brew.. they Love the Jail especially at Christmas .. Would I take on a contract to bump someone off !? ofcourse - £50K - then I would get the Junkie to do it.
2006-12-19 07:35:12 · answer #4 · answered by Anonymous · 1⤊ 1⤋
it depends,some get a freebie for just being alive and a conract is something new i hear
2006-12-19 07:32:36 · answer #5 · answered by Drew 4 · 0⤊ 1⤋
i dont think i would kill a person oh well i lied i would kill wsome of the nasty people in the world that have killed many innocent people and my price would be £250,0000
2006-12-19 07:32:41 · answer #6 · answered by nicolefrenzy 6 · 1⤊ 0⤋
I wouldn't kill any body for any reason or price. That's horrible.
2006-12-19 07:30:38 · answer #7 · answered by laney 5 · 0⤊ 1⤋
actually i offer a buy one get one free deal at xmas time!valid until 3 jan £30.00/ $45.00
2006-12-19 07:34:09 · answer #8 · answered by Anonymous · 1⤊ 0⤋
If it were my hubbys x-wife, Hmmmm...... I dont know if I could do it at all. However, paying someone??? Now there is a nice fantasy!
2006-12-19 07:31:08 · answer #9 · answered by thelaundryfairy 3 · 1⤊ 0⤋
5000 no women no kids, thats the rules
2006-12-19 09:26:28 · answer #10 · answered by Anonymous · 0⤊ 0⤋