Basic uncertainty principle problem?

Question

If the position of a particle of mass 10^-3g can be determined to an accuracy of = 10^-5cm. Calculate the time period for the particle to move a detectable distance.

Answer 1

The time it takes that particle (within the bounds of uncertainty) to move double the distance of uncertainty. (Double do to the uncertainty of both the particles position and the position of the point of reference.) This will give you the MINIMUM time needed to know 100% that a particle has moved. With almost one hundred percent certainty one can logically deduce that a particle has moved before you can detect it. (Since in order for this to not be true the particle must be at absolute zero temperature having zero potential energy.)

MDP

Answer 2

I am not sure to can but I give you some advices

First the principle says delta x *delta mv =h/4pi

we can calculate delta mv since

delta mv = h/(4pi *delta x) in MKSA units h = 6.6210^(-34) Js
delta x = 10^-7m

so delta mv = 6.6210^(-27) kg m /s
as m (10^-6)is known delta v = 6.62 10^(-21) m /s

Sorry?i can not go beyond