Solve 4 cos x – 3 = 0, when 0≤ x ≤ 360˚?
2006-12-18 15:24:10 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
cos x = 3/4, you mean?
The cosine is positive in the first and fourth quadrants.
2006-12-18 15:26:52 · answer #1 · answered by ? 6 · 0⤊ 0⤋
4 cos x – 3 = 0 upload 3 to the two factors 4 cos x=3 divide by using 4 cos x=3/4 x=arccos 3/4=40-one.4°=.7227 radians it is interior the 1st or 4th quadrant so it could additionally be x=5.560 radians or 318.6°
2016-12-15 03:59:41 · answer #2 · answered by binford 4 · 0⤊ 0⤋
4 cos x - 3 = 0
cos x = 3/4
basic angle: 41.4096
since cos x > 0, and range of x is between 0 and 360,
x=41.4096
= 41.4
or x= 360-41.4096
= 318.5904
= 318.6
2006-12-18 19:16:29 · answer #3 · answered by christismyrock 2 · 1⤊ 0⤋
4 cos x -3 = 0
4 cos x = 3
cos x = 3/4
cos x = 0.75
x = (cos)-1(0.75)
x = 41.40962 degree.
2006-12-18 15:33:13 · answer #4 · answered by CLOUND 3 · 0⤊ 0⤋