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If this helps, the polynomial is:

f(x)=5x^3 +3x^2 -7x +18

2006-12-18 14:31:27 · 4 answers · asked by C 1 in Science & Mathematics Mathematics

4 answers

Find the roots that are integers.
Test +/-18,+/-9,+/-6,+/-3,+/-2,+/-1 for possible roots.

2006-12-18 14:33:45 · answer #1 · answered by knock knock 3 · 1 0

You have your f(x) polynomial in a standard form. Knock
knock lists the possible integral roots for your particular polynomial. If A IS an integral root of your polynomial then f(A) does = 0, as raj states.

The integer roots of a polynomial must be a divisor of the
constant term. (That's what Knock knock listed.) Noone is saying that there is an integer root, just what set they must come from. Further, any rational root must come from the divisors of the constant term for a numerator, and the divisors of the leading term for the denominator.

Finally, FWIW your polynomial apparently has one neg root around x = -2, and 2 conjugate non-real roots.

2006-12-18 23:21:41 · answer #2 · answered by answerING 6 · 0 0

to find all those integers which will reduce the poly to zero

2006-12-18 22:33:54 · answer #3 · answered by raj 7 · 0 1

u factorise first

2006-12-18 22:33:35 · answer #4 · answered by miss_ooO 2 · 0 1

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