Solve tan^2 x =1, when 0≤ x ≤ 360˚?

8 ⤊

2006-12-18 12:50:25 · 3 answers · asked by thomasgraham880 1 in Science & Mathematics ➔ Mathematics

√tan^2x=±√1
tan x=±1
x=π/4, 3π/4, 5π/4, and 7π/4
x=45°, 135°, 225, and 315°

2006-12-18 13:03:31 · answer #1 · answered by Anonymous · 4⤊ 0⤋

tan^2 x = 1 <==> tan x = +/- 1. So solutions are 45Ë, 135Ë, 225Ë and 315Ë.

2006-12-18 12:58:23 · answer #2 · answered by Scarlet Manuka 7 · 2⤊ 0⤋

tan^2 x=1
tan^ x=+/-1
x=45Â°, 135Â°, 225Â°, 315Â°

2006-12-18 12:58:29 · answer #3 · answered by yupchagee 7 · 2⤊ 0⤋