toss a ball upward at 30m/s no air drag ,ball will be up in the air for how many seconds?

1 ⤊

2006-12-18 12:31:43 · 5 answers · asked by Jose C 1 in Science & Mathematics ➔ Physics

6 seconds

2006-12-18 12:34:39 · answer #1 · answered by kurticus1024 7 · 0⤊ 0⤋

3 second

2006-12-22 04:36:34 · answer #2 · answered by farjad 1 · 0⤊ 0⤋

s = 0 = ut + 1/2 g t^2 => t = 0, -2u/g. So with u = 30 m/s, g = -9.81 m/s^2 we gt t = 60/9.81 = 6.1 seconds.

2006-12-18 20:35:57 · answer #3 · answered by Scarlet Manuka 7 · 0⤊ 0⤋

Using v=u+at,
0=30-9.81t
t=3.06 s to reach maximum height
So to get back to the ground will take another 3.06 s.
Total time will be 6.12 seconds

2006-12-18 20:39:46 · answer #4 · answered by james t 2 · 1⤊ 0⤋

3.0612244 seconds I think... But I think I am wrong...

2006-12-18 20:35:38 · answer #5 · answered by Mattimos 3 · 0⤊ 0⤋