Math problem!!!???

Question

Four times the sum of three consecutive integers is 48.

What are the integers???

Answer 1

Your equation is 4(x + x+1 +x+2) = 48
So, 3x +3 = 12
3x = 9
x = 3
The integers are 3, 4, and 5

Answer 2

Four times the sum is 48; therefore, the sum is 12. The midle of the three consecutive is the average value of 3 numbers=12/3=4. The integers are 3,4,5.

Answer 3

3 4 5

Answer 4

3 4 5

Answer 5

First do 4/48 and you get 12. So what three consecutive numbers equal 12. 3+4+5=12. 4*12= 48

Answer 6

Let's rewrite the problem into numerical data:

First number = x+1
Second number = x+2
Third number = x+3

4(x+1+x+2+x+3) = 48

First: combine "like" terms in the parenthesis; use distribution by multiplying:

4(3x) + 4(6) = 48
12x + 24 = 48

Second: subtract 24 from both sides; divide 12 by both sides:

12x + 24 - 24 = 48 - 24
12x = 24
12x/12 = 24/12
x = 2

Third: take 2 and replace it with "x" for the three equations:

first: 2+1 = 3
second: 2+2 = 4
third: 2+3 = 5

Answer 7

Integers is another name for whole numbers, as in 1, 2, or it can be negative -1, -230. Intergers are therefore not fractions or decimals. The question is asking

4(x + x+1 + x+2) = 48 divide both sides by 4
(x + x+1 + x+2) = 12 simplify the left
3X+3 = 12 simplify by subtracting 3 from both sides
3X = 9 simplofy by dividing both sides by 3
x = 3

ta da!

Answer 8

divide 48 by 4 to get 12
what 3 consecutive numbers add to give you 12?
divide by 3, add 1, subtract 1
3, 4, 5
4(3+4+5) = 48

Answer 9

3+4+5 = 12

12*4 = 48.

Answer 10

Let the middle integer be x.

4((x-1)+x+(x+1))=48
3x=12
x=4
3,4,5