Wut volume of 02 gas is consumed inthe combustion of 65.6L ofpropane gas, C3H8, if both gases are measured@STP

Question

Okay... Here's the question again..

What volume of O2 gas is consumed in the combustion of 75.6L of propane gas, C3H8, if both gases are measured at STP (1atm, 0 degrees celcius)

C3H8(g) + 5 O2(g) ---->> 3 CO2(g) + 4H2O(g)

Thanks!

Answer 1

Since temperature and pressure are constant, the volume and number of moles are proportional. Since you need 5 moles of oxygen for every mole of propane, it's simply 5 x 75.6 or 378 L.

Answer 2

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