An investment increases by 10% then decreases by 6% to £25850. What was the orginal amount invested?

Question

any help to this question would be gratefully received....its doing my head in!

Answer 1

Before the 6% decrease:

.94 x = 25850
x = 27500

Then, before the 10% increase:

1.1 x = 27500
x = 25000

So the original investment was £25000.

Answer 2

Set it up algebraically. A 10% increase is the same as multiplying by 110%, or 1.1. A 6% decrease is the same as multiplying by 94%, or 0.94. If the original investment was x, just solve 1.1*0.94*x = 25850. The nice thing about percents in a situation like this is that it doesn't matter what order you take them in, because multiplication is commutative.

Answer 3

You can write this as an equation with the original investment as x. A decrease of 6% is the same thing as multiplying by .94, and an increase of 10% is the same as multiplying by 1.1.

(.94x 1.1)x = 25850
x = 25850/1.034
x = 25000

The original investment was 25000.

Answer 4

A x .94=25850
A=25850/.94=27500

B x 1.1=27500
B=27500/1.1=25000

Answer 5

initial investment=x
increases to 1.1x
decreases to .94*1.1x=1.034x= £25850
x=25850/1.034=£25,000

Answer 6

25000
x*(110/100)=y;
y*((100-6)/100)=25850;
y=25850*(100/94);
x=y*(100/110);
x=25850*((100*100)/(110*94))
x=25000
exactly