im confused on a math question?

Question

|x+2| -4 = 3


i need help on the answers for both "sides" of this problem meaning that what would the answer be if the solution being 3 was changed to -3???

ahh so confusing! thanks!!!

Answer 1

|x+2|=7
The answer is x=5, -9.

When you plug both in for x you get:
|5+2|=7
|7|=7
7=7
and
|-9+2|=7
|-7|=7
7=7

Answer 2

Start by adding 4 to both sides to get |x + 2| = 7. It is not the 3 that needs to be considered as a negative, but rather this 7. You need to solve x + 2 = 7 and x + 2 = -7 to get the two answers, which are x = 5 and x = -9.

Answer 3

Just follow these simple steps. I had problem with this too, i had this for homework the other day.
-You get two answers by changing the solution into -3. Since its absolute value.
So your two problems are lx+2l -4=3 & lx+2l-4= -3

Now, lets just start with your first problem, step by step:
lx+2l -4=3
1.) Place -4 to the other side of the equal sign, which then changes the sign to a +positive sign. Which makes the problem now look like lx+2l=3+4
2.) lx+2l=3+4 You'd solve this problem. Which so far looks like
lx+2l =7
3.) Your problem now looks like lx+2l =7. Now you pretend there is no absolute value sign, and so your problem would now look like x+2 =7. Solve this.
4.) Your 1st answer is x=5. This is b/c you subtract 2 by 7, which equals 5.

Your Second Problem:
1.) lx+2l-4= -3
2.) You would deal with the non-absolute value part first. So you would add 4 to -3. Which equals 1.
3.) Your problem is now lx+2l= 1. So you solve this by pretending the absolute value signs aren't there. So your problem would look like x+2=1. So you solve this by subtracting 2 by 1.
4.) Your answer is x=-1.

Answers:
Ans # 1: x = 5
Ans # 2: x = -1

Hopefully this helped, GOOD LUCK!

Answer 4

The vertical bars on either side of the expression mean that you are to take the positive value of the expression. The vertical bars are a function called "absolute value".

Therefore, if you need to change anything, it is to change the value of x within the absolute function. First, treat the entire ABS function as it it were a variable:

ABS(x+2) - 4 = 3
then
ABS(x+2) = 3+ 4 = 7

So, we have x+2 = 7 and/or -(x+2) = 7

solve for both possibilities

Answer 5

First: get rid of the aboslute sign by rewriting the equation:

x + 2 - 4 = 3

x - 2 = 3

Second: solve for "x" by leaving it on one side by itself. Add 2 to both sides:

x -2 + 2 = 3 + 2
x = 5

Now, change the sign of 3 into -3 and solve for "x" again:

x + 2 - 4 = -3
x - 2 = -3
x - 2 + 2 = -3 + 2
x = -1

Answer 6

well first you must add 4 to both sides. then subtract 2 from bith sides, then you get x =5:
(x+2)-4 = 3
+4 +4
(x+2) = 7
-2 -2
x= 5

Answer 7

|x + 2| - 4 = 3
|x + 2| = 7
x + 2 = 7 so x = 5
or -(x + 2) = 7, so x + 2 = -7 so x = -9

x = 5 or -9

|x + 2| - 4 = -3
|x + 2| = 1
x + 2 = 1 so x = -1
or -(x + 2) = 1 so x + 2 = -1 so x = -3

x = -1 or -3

Answer 8

to function or subtract fractions the two fractions choose a trouble-unfastened denominator (backside area of the fraction) those would properly be won by using multiplying the two or the two fractions by using some style of a million (conserving in techniques that something like 3/3 = a million) multiplying by using one purely variations the visual charm of the fraction no longer the cost itself. So for the 1st one: The denominators are 4 and 12, because 4*3=12 you need to use 12 by using fact the hassle-unfastened denominator. fifty 3/4*(3/3) + sixty one/12 = ? 159/12 + sixty one/12 = 220/12. some instructors require you to shrink the fraction-which lower back would not substitute the cost of it, purely the visual charm. for this reason the two numbers are divisible by using 4 so divide the two the best and backside of your fraction by using 4 and you get 55/3, the stunning answer. the comparable would properly be accomplished with 80 one/2-40 seven/8. the hassle-unfastened denominator is 8 by using fact 2*4 = 8 so purely multiply 80 one/2 by using 4/4 and you get: 324/8 - 40 seven/8 = 277/8

Answer 9

first simplify

|x+2|=3+4
|x+2|=7
then look at it in terms of intervals
then look at it both ways…
if x>-2, x must be equal to 5. |5+2|=7
if x<-2, x must be equal to -9…|-9+2|=7…==> |-7|=7

So x is equal to 5 or -9

if the right side was switched to -3…though I don't understand why you would do that…
then |x+2|=-3+4
|x+2|=1
so x can be -1 or -3

Answer 10

It's easy because we apply an standar theorem about absolute value: Given a real number A>0, |X|=A if and only if X=A or X=-A.
In your case, |x+2| = 7 if and only if x+2 = 7 or x+2 = -7; That is x = 5 or x = -9.

....

Answer 11

|x+2| = 7 so x is either -9 or +5 (if right side is +3)

|x+2| = 1 so x is either -1 or -3 (if right side is -3)