find the 50th term of the sequence 7,4,1,-2,-5,...?

Question

find the exact zeros of the function y = 6x2 + 5x - 3

use the qyadratic formular to solve the equation
16x2 - 8x = 3

Answer 1

1. the common difference is -3, so the 50th term is 7 -3(49) = 10 - 3(50) = -140

2. solve 0 = 6x² + 5x - 3. using quad formula, x = -5/12 ± (1/12)√[25 - 4(6)(-3)]
x = -5/12 ± (√97)/12

3. solve 0 = 16x² - 8x - 3 just like #2.

Answer 2

Nth term = 7-3(n-1)
50th term=7-3*49=7-147=-140

Answer 3

an = a1 + (n - 1)d

an = 7 - 3(n - 1)

a1 = 7 - 3(1 - 1) = 7 - 3(0) = 7 - 0 = 7
a2 = 7 - 3(2 - 1) = 7 - 3(1) = 7 - 3 = 4
a3 = 7 - 3(3 - 1) = 7 - 3(2) = 7 - 6 = 1
a4 = 7 - 3(4 - 1) = 7 - 3(3) = 7 - 9 = -2
a5 = 7 - 3(5 - 1) = 7 - 3(4) = 7 - 12 = -5

If you were to continue this

a(50) = 7 - 3(50 - 1) = 7 - 3(49) = 7 - 147 = -140

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y = 6x^2 + 5x - 3

x = (-b ± sqrt(b^2 - 4ac))/(2a)

x = (-5 ± sqrt(5^2 - 4(6)(-3)))/(2(6))
x = (-5 ± sqrt(25 + 72))/12
x = (-5 ± sqrt(97))/12
x = (1/12)(-5 ± sqrt(97))

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16x^2 - 8x = 3
16x^2 - 8x - 3 = 0

x = (-b ± sqrt(b^2 - 4ac))/(2a)

x = (-(-8) ± sqrt((-8)^2 - 4(16)(-3)))/(2(16))
x = (8 ± sqrt(64 + 192))/32
x = (8 ± sqrt(256))/32
x = (8 ± 16)/32
x = (-8/32) or (24/32)
x = (-1/4) or (3/4)

Answer 4

This admired series of numbers is time-honored because the Fibonacci huge style (or Fibonacci series) and may be represented mathematically as Fn= Fn-a million + Fn-2... following this formula, the subsequent 3 numbers on your series is for this reason 21, 34 & fifty 5. desire this helps! all the perfect, Peter G

Answer 5

The 50th term is -137; you're descending in increments of 3.

Answer 6

The 50th term is -155

Answer 7

a) -140

b) .4 and -1.2

c) .75 and -.25