OK, you have to be pretty tricky to get this one. Let's list out all the possible combinations, and their sums:
1, 1, 36 (unlikely!!) - sum 38
1, 2, 18 - sum 21
1, 3, 12 - sum 16
1, 4, 9 - sum 14
1, 6, 6 - sum 13
2, 2, 9 - sum 13
2, 3, 6 - sum 11
3, 3, 4 - sum 10
Now, since the sum in itself wasn't enough to give Paul the answer, the sum must appear twice or more in this list. The only one that does is 13, so the two possibilities are:
1, 6, 6 or 2, 2, 9.
Steve's final statement implies that there is a single eldest child, so the ages must be 2, 2 and 9.
2006-12-18 10:47:09
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answer #1
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answered by Scarlet Manuka 7
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