2006-12-18 06:33:43 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
there are seven.
2006-12-18 06:42:26 · update #1
Energy level number n can hold up to 2 x n^2 electrons
2006-12-18 06:41:40 · answer #1 · answered by Anonymous · 0⤊ 0⤋
right here table develop into given to us in college fairly your time in the past. There are 7 shells. optimal No. of electrons in line with shell is as follows... ok. #a million. = 2 x a million² = 2 Electrons. L. #2. = 2 x 2² = 8. M. #3. = 2x 3² = 18. N. #4. = 2 x 4² = 32. O. #5. = 2 x 5² = 50. * P. #6. = 2 x 6² = seventy 2. * Q. #7. = 2 x 7² = ninety 8. * * = Theoretical skill
2016-11-27 02:29:57 · answer #2 · answered by Anonymous · 0⤊ 0⤋
The first level holds two, the second holds eight, the third holds 18.
You can figure out how many each level will hold by the equation 2n^2 where n represents the energy level.
2006-12-18 06:41:07 · answer #3 · answered by anonymous 6 · 0⤊ 0⤋
Or . . . simply ;
1st 2
2nd 8
3rd 18
4th 32
5th 32
6th 32
7th 32
Note: The elements last energy level will not have more than 8 electrons not matter the max. allowed.
Get an "A".
2006-12-18 09:21:57 · answer #4 · answered by teachr 5 · 0⤊ 0⤋