What percent by weight of CCl4 (carbon tetrachloride) is carbon (C)? (C, 12; Cl, 35)?

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What percent by weight of CCl4 (carbon tetrachloride) is carbon (C)? (C, 12; Cl, 35)?

(see above..)

Thanks so much.

2006-12-18 06:12:45 · 4 answers · asked by Ryan 1 in Science & Mathematics ➔ Mathematics

4 answers

add the atomic weight together

C: 12
Cl: 35 (4)
________
152

then take carbon and divide into total weight

12/152

then multiply by 100 to get percent

0.0789x100 = 7.89%

2006-12-18 06:17:59 · answer #1 · answered by xashleyleyx 4 · 0⤊ 0⤋

C =14 and 4 Cl = 35*4 =140

So CCl4 weights 154 and % of C is 14*100/154 = 9.1 %

2006-12-18 14:17:28 · answer #2 · answered by maussy 7 · 0⤊ 1⤋

12+35(4)= 152
C=12/152=7.9%
Cl4= 140/152=92.1%

2006-12-18 14:18:57 · answer #3 · answered by 7 · 0⤊ 0⤋

answer = 12 / (12+ (4 x 35.5))

2006-12-18 14:31:44 · answer #4 · answered by Radagast97 6 · 0⤊ 0⤋