positive intergers?

Question

Given positive intergers a and b such that ab=40,000 and neither a nor b is divisible by 10, what is a+b?

Answer 1

ab = 40,000 = 2^6 * 5^4.

Neither a nor b can have both 2 and 5 as factors. So a=2^6=64, and b=5^4=625 (or the reverse).

a+b = 689.

Answer 2

this is a very simple question?
it can be solved by simple factorization mathametics as shown below
40000 = 2^6 * 5^4
now , since a and b are positive integers so we must have a and b factors of 40000
or in other words we can say that a and b will have factors out of 2^6 and 5^4 so we have to make the pairs of these factors suchat neither of two are divisible by 10 and this can be posibble by taking factors as 2^6 and 5^4
or let a=2^6 and b =5^4
there fore a+b =2^6 +5^4 =625 + 64 = 689

Answer 3

40000
To get rid of each zero, divide it by 5 or 2 (10=2x5)

40000/(5x5x5x5) = 64
2 numbers are 64 and 5x5x5x5=625
a+b =64+625=689

Answer 4

Well, 40000 = 64*625, so a + b = 689.

Answer 5

Here's a hint. What's the prime factorization of 40,000? That is, come up with a bunch of prime numbers that multiply together to make 40,000. You'll have to repeat some.