How can you solve this?

Question

Solve this system of equations

x+y+z= negative 1
3x-2y-4z=16
2x-y+z=19

Answer 1

You need to use elimination
x+y+z=-1
3x-2y-4z=16
Multiply the first equation by 2. Combine with the second equation. Y is eliminated.
You are left with 5x-2z=14
Combine the first and third equation to eliminate Y and Z
You are left with
5x-2z=14
3x+2z=18
8x=32
x=4
Now you can insert 4 for X and use the same process.
(4)+y+z=-1
2(4)-y+z=19
12+2z=18
-12 -12
2z=6/2
z=3
Plug in Z and X into any equation and that will equal Y
(4)+y+(3)=-1
7+y=-1
-7 -7
y=-8
Check the solutions
4+-8+3=-1
3(4)-2(-8)-4(3)=16
2(4)-(-8)+3=19

Answer 2

Use any of the three equations and solve for any variable. Let's say in one equation you solved for Z. Use what z equals and plug that into the other two equations where Z is. Now you have 2 equations with 2 variables. Do the same thing.

Answer 3

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