There are 47 possible numbers that can be chosen in a correct series of 5 drawn numbers plus one Mega number. How could a calculation or formula be applied to estimate these? With 47 possible numbers the combinations must be massive, but is there a way to check exactly how many 5 number combinations are possible using the 47 numbers?
Also, I would imagine that in order to calculate the odds, all the winning number series would have to be known, right or not? I would assume that it would be similar in poker, how many times a royal flush or 4 of a kind would turn up predictively
Any math whiz care to offer a formula to the problem?
2006-12-18 04:10:56 · 7 answers · asked by mrfrudd2006 3 in Science & Mathematics ➔ Mathematics
Assuming that two numbers can't repeat, then your probability for getting just the first one correct would be 1/47, just the second one 1/46, the third 1/45, the fourth 1/44, and the fifth 1/43. To find the probability of getting all of them right can be found by multiplying them together: 1/(47*46*45*44*43)
The formula can be written using factorials. With x possible numbers and n numbers drawn, you can say that the probability of winning is p = (x-n)! / x! You do not need to know what the winning numbers series is. A similar formula will also work with poker, though it is rather difficult to calculate in your head.
So your chances of winning are 1/184,072,680
These are obivously not very good odds, and you are actually more likely to die in a car accident on the way to the store to buy a lottery ticket than actually winning it.
2006-12-18 04:21:56 · answer #1 · answered by Anonymous · 3⤊ 0⤋
RE:
How To Calculate Winning Odds In CA Super Lotto Plus?
There are 47 possible numbers that can be chosen in a correct series of 5 drawn numbers plus one Mega number. How could a calculation or formula be applied to estimate these? With 47 possible numbers the combinations must be massive, but is there a way to check exactly how many 5 number...
2015-08-04 06:21:24 · answer #2 · answered by Lamond 1 · 1⤊ 0⤋
Does the order of the 5 numbers matter? The answers above mine assume that it does.
If order doesn't matter, then your probability of winning is:
5/47 * 4/46 * 3/45 * 2/44 * 1/43 = 1 / 1,533,939.
Explanation: The first number has to be one of the 5 that you picked, so 5/47. The second number has to be one of the remaining 4 (out of 48 left to draw from), so 4/46. Etc.
This is basically taking the 184,072,680 combinations that others figured out, and dividing by 5!=120 because for any 5 numbers there are 5!=120 ways to order them.
2006-12-18 05:12:27 · answer #3 · answered by Anonymous · 3⤊ 0⤋
The number of possible combinations: 47*46*45*44*43. (47 choices for first number, 46 for the second etc). So the chances of winning are 1 in that number.
It is interesting that any 5 number sequence has the same chance of winning. So if you choose 1-2-3-4-5 you have the same chances of winning as anyone else.
2006-12-18 04:14:25 · answer #4 · answered by raz 5 · 1⤊ 1⤋
well, i'm not from california, so i'm not exactly sure how your lotto system works, however...
if a number can be repeated, the answer is simple. if no number is repeated, it is 47^5 or 47 times 47 times 47 times 47 times 47 times whatever the number of possibilities for the mega number.
the answer here is 229,345,007 times the number of possiblities for the mega number
if a number cannot be repeated, it is 47 times 46 times 45 times 44 times 43 times the number of possibilities for the mega number.
184,072,680 times the number of possibilities for the mega number.
in dealing with the royal flush, the answer is 5/13 times 4/51 times 3/50 times 2/49 times 1/48, and that is with five card draw. the meaning here is that with the first card, it can be any suit, but has to be a 10, jack, queen, king, or ace. the odds of this being your first card is 5 out of 13. after the suit is chosen with that card, you now can only get the same suit. you have 4 choices left and there are 51 cards left in the deck. every next card, you have one less card in the deck, but you also have one less choice for the card that you need. hence, the decreasing numbers.
there are 120 out of 77968800 possibilities.
every 649740 hands you play, you should get one royal flush.
2006-12-18 04:31:30 · answer #5 · answered by Justin H 2 · 1⤊ 1⤋
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How about a sure thing-put the money you would have spent on a lotto ticket in the bank, you cant go wrong!
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