2006-12-18 03:45:52 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
2KMnO4 + 3H2O2 -----> 2Mn(OH)2(s) + 2KOH + 4O2
If you have a acidic solution, acid will react with Mn(OH)2 and KOH, it means :
6H^+ + 2KMnO4 + 5H2O2 ---> 2Mn^2+ + 2K^+ + 5O2 + 8H2O
But the main reaction is something that I had mentioned before.
2006-12-18 04:43:39 · answer #1 · answered by Ash 2 · 0⤊ 0⤋
KMnO4 is a powerful oxidising agent, and, in mildly acidic solution, forces H2O2 to be a reducing agent. Oxygen gas is seen bubbling off.
2(MnO4)- + 5H2O2 + 6H+ ----> 2Mn2+ + 5O2 + 8H2O
This is not the same as the catalytic decomposition of H2O2 by MnO2.
2006-12-18 12:43:54 · answer #2 · answered by Gervald F 7 · 0⤊ 1⤋
KMnO4 remains unchanged.
H2O2 is decomposed to water and Oxygen
Reaction:
KMnO4 +2 H2O2---> O2 + KMnO4 +2H2O
If you ignite a matchstick over the test tube, it burns brightly because of the oxygen evolved.
Although the purple colour of the solution remains unchanged.
2006-12-18 11:53:07 · answer #3 · answered by Som™ 6 · 0⤊ 1⤋
KMnO4 +2 H2O2---> O2 + KMnO4 +2H2O
You would have purple water after the O2 left.
Usually MnO2 is used as the catalyst to release O2 fro H2O2
2006-12-18 11:52:06 · answer #4 · answered by science teacher 7 · 0⤊ 2⤋