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20 answers

Slope:
m=(y2-y1)/(x2-x1)
m=(10-1)/(-4-2)
m=-9/6
m=-3/2

2006-12-18 04:20:56 · answer #1 · answered by Anonymous · 4 1

in case u don't follow the formula others have used, you can use the formula y = mx + c which u might recognise.

which is the way of formulating any graph equation

ok so finding the slope means finding the gradient which is 'm' in the equation.

because it is the slope following the line passing through these two points then we end up with the same gradient in both equations.

so with (2, 1) means x= 2, y= 1 and (-4, 10) x = -4, y= 10.

then substitute these values into the equation y= mx + c
so with (2, 1) we get 1= 2m + c (1)
and (-4, 10) we get 10= -4m + c (2)

so first with (1) i'm going to takeaway 1 from both sides which equals:
1 - 1 = 2m + c -1 to simplify as:
0 = 2m + c - 1

then with (2) we are going to takeaway 10 from both sides which equals:
10 - 10 = -4m + c -10 to simplify as:
0 = -4m + c -10

so because 0 = 2m + c -1 and 0 = -4m + c - 10 it has to be that:

2m + c - 1 = -4m + c -10 because they both equal the same = 0

first we can get rid of c on both sides by taking away c from both sides:

2m + c - 1 - c = -4m + c - 10 - c which simplifies as:
2m -1 = -4m -10

now add 4m on both sides:
2m + 4m -1 = -4m + 4m -10 which simplifies as:
6m -1 = -10

then add 1 on both sides:
6m -1 + 1 = -10 +1 which simplifies as:
6m = -9

then divide by 6 on both sides:
6m/6 = -9/6 which simplifies as:
m = -9/6

-9/6 can be simplified to -6/3 (divide both numbers by 3)

therefore answer is m = -6/3 which is what the slope (gradient) is

2006-12-18 09:06:41 · answer #2 · answered by emicarina 2 · 0 0

y2 - y1/ x2 - x1 4 - 4/ 2 - (-6) = 0/8 = 0 A line with a slope of 0 is a horizontal line. If the 0 were in the denominator, the slope could have been "undefined". i desire that helps. good luck.

2016-10-15 04:23:20 · answer #3 · answered by lipton 4 · 0 0

First: distinguish the slope formula:

m = (second y - first y)/(second x - first x)

Second: place the points in the appropriate spot within the formula and solve according to order of operations:

m = (10 - 1)/(- 4 - 2)
m= 9/-6; m = -9/6

Third: simplify the fraction into lowest terms:

m = -3/2

2006-12-18 04:49:00 · answer #4 · answered by ♪♥Annie♥♪ 6 · 0 0

your answer goes
solution
here
let the given points be A(2,1) and B(-4,10)
we know that,
slope (m) ={(Y2-Y1)/(X2-X1)}
={(10-1)/(-4-2)}
={9/-6}
=(3/-2)
there fore slope of line AB is (3/-2)

2006-12-18 04:29:11 · answer #5 · answered by aakriti b 1 · 1 0

10-1=9
-4-2=-6

-3/2

2006-12-18 03:46:43 · answer #6 · answered by Amanda 4 · 1 0

Assuming a straight line running through both points.

Slope is defined as

(change in y value)
--------------------------
(change in x value)

For two points with coordinates (x(1), y(1)) and (x(2), y(2))

Slope = (y(2) - y(1))/ (x(2) - x(1))

In your problem
x(1) = 2
y(1) = 1
x(2) = -4
y(2) = 10

Substituting

Slope = (10 - 1)/(-4-2)
Slope = 9/(-6)
Slope = -3/2
in other words -1.5

2006-12-18 03:30:29 · answer #7 · answered by Dr Bob UK 3 · 2 0

the slope of m of a line passing through the points (X1 +Y1) and (X2+Y2) is given by
m= (Y2-Y1)/(X2-X1)
X1=2 Y12=1
X2=-4 Y2=10

m= 10-1/-4-2
=9/-6
=-3/2
m which is the slope = -1.5

2006-12-18 03:43:44 · answer #8 · answered by yason 2 · 1 0

The 'y' co-orddinates are subtracted and then divied by the the subtracted 'x' co-ordinates.
1-10
______ =
2--4

-9
___ =
6

Ans: -3/2

2006-12-19 06:55:47 · answer #9 · answered by lenpol7 7 · 0 0

(1-10)/(2--4)=-1.5

y=mx+c- Eqn of a line

Y1=mx1+c

Y2=mx2+c

=> Y1-y2=m(x1-x2)

(Y1-Y2)/(X1-x2)=m

M is the slope

2006-12-20 01:30:31 · answer #10 · answered by Bobby 2 · 0 0

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