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Let by P, Q polinomials functions ,then f(x)=P(x)/Q(x) is rational function & g(x)=sqrt(P(x)) is irrational function. ok!

2006-12-18 03:09:01 · answer #1 · answered by grassu a 3 · 0 0

Unlike rational and irrational numbers, the term "irrational function" is not used. The definitions above for rational functions are correct, a ratio of polynomials. Sqrt(x) is not a rational function, but it is an algebraic function, being a solution to y^2-x=0. The function e^x is not a rational function, but is called a transcendental function. The term "irrational function" is not commonly used.

2006-12-18 06:00:17 · answer #2 · answered by a_math_guy 5 · 0 0

A rational function can be expressed a ratio of polynomials.

Therefore I'd assume an irrational function cannot.

2006-12-18 02:51:44 · answer #3 · answered by Jim Burnell 6 · 1 0

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