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construct an annotated derivation for the arguement :
1. (P@Q)@R
2. (S@Q)>T
3. ~T
therefor 4. P@R

2006-12-18 02:42:42 · 3 answers · asked by jules 1 in Science & Mathematics Mathematics

3 answers

4. P@Q (1, simplification)
5. R (1, simplification)
6. P (4, simplification)
7. Q (4, simplification)
8. ~(S@Q) (2, modus tollens)
9. ~S v ~Q (8, DeMorgan's Law)
10. ~~Q (7, Double Negation)
11. ~S (9, 10, Disjunctive Syllogism)

12. P@R (6, 5, Conjunction)

[Note; are you sure you wrote the question down correctly? We didn't seem to require #2 or #3 for the conclusion.

2006-12-18 02:51:21 · answer #1 · answered by Puggy 7 · 1 0

i'd be satisfied to help, yet please make sparkling what you propose by technique of your symbols ~ = no longer (i assume) @ = and (?) > = implies (?) < = or(?) the surprising one is the single perplexing me the most. also, are there any axioms to coach this from, or merely coach this from the the same old tautologies?

2016-11-27 02:03:43 · answer #2 · answered by Anonymous · 0 0

I don't understand your notation. What'2 @? And? Or??

Ana

2006-12-25 08:55:29 · answer #3 · answered by Ilusion 4 · 0 0

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