what is the test of divisibility of 18?

Answer 1

It should be divisible by 2 and 9

for it to be divisible by 2 unit digits should be even 0,2,4,6 or 8

and sum of digits should be divisible by 9 to be divisible by 9

so both above condition should be satisfied

Answer 2

Divisibility Rules For 18

Answer 3

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No. Since 3 and 4 are coprime, then using such a division test would work. However, 2 is a factor of 6, so anything divisible by 6 is going to be divisible by 2 also. But not all numbers that are divisible by 6 are divisible by 12. For example, 18 is not divisible by 12.

Answer 4

1+8=9
9 is divisible by 3
there4 18 is a factor of 3
some eg's-
27, 2+7=9
15, 1+5=6
30, 3+0=3

divisibility of 18
its sum should be divided by 3


like 18 1+8 = 9 it is divisible by 3
36 3+6= 9

Answer 5

1+ 8 = 9 so it is divisible by 3 and 9

Answer 6

it should be divisible by 2 as well as 9.

Answer 7

you can test the divisiblity by 18 by breaking it into its factors, which are coprime to eachother.
If the above statement sounds a bit like an alien language, use this(its the same what i wanted to say above but in simple terms): just check the divisibilty by both 9 & 2 (since, 9*2 = 18)
Divisibility test for 9 is : the sum of digits of the number is divisible by 9
Divisibilty test for 2 is : I don't need to tell you this :d

Answer 8

Two necessary condtitions

1) All digits add up to a number divisible by 9 not just 3

2) The number is even

Answer 9

it must be divisible by 2&9 i.e;it must be an even number whose sum of the digits is a multiple of 9

Answer 10

Dividibility gives u Pain and make u nrvas .