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" Ever-increasing amount of charges would lead to ever-increasing potential difference between two plates. If the capacitor’s working voltage is exceeded, or the strength of the ever-increasing electric field is more than what the dielectric can withstand, the capacitor is most likely to be spoiled. " So how do we know when the amount of charges and the voltage is exceeded? And how do we protect capacitors from this?

2006-12-17 19:42:08 · 4 answers · asked by iamlonely 1 in Science & Mathematics Physics

4 answers

All capacitors come with a voltage rating. That is the recommended maximum operating voltage for the capacitor. In general, the capacitance of a capacitor of a given size will vary roughly inversely as the voltage rating. So you might find a capacitor of 10µF at 150V at about the same size as a 100µF at 15V. The protection of the capacitor comes from the design of the circuit. The designer will know the voltage levels the capacitor will be working at. The designer will pick a capacitor of high enough voltage rating so that its maximum voltage will not be exceeded. Usually, the rating used is higher than the known maximum voltage in the circuit in order to provide a safety factor. However, the rating itself includes some safety factor. A capacitor rated at 100v will not suddenly blow up at 110V.

Different dielectrics have different breakdown field strengths, with glass, ceramic and mica being the strongest, and the thin dielectric coating on an electrolytic capacitors being the weakest.

2006-12-17 19:53:02 · answer #1 · answered by gp4rts 7 · 0 0

A monostable has one reliable state and an astable has 2. in actuality the 555 astable, whilst activated reasons a set of oblong pulses. those pulses turn an LED or buzzer on and stale continuously, e.g. the LED will get rid of darkness from and then extinguish and then proceed this development. With the monostable, whilst it particularly is activated it reasons a buzzer to stay to tell the story for a desperate volume of time making use of a capacitor. you will no longer would desire to understand the makings of what's interior the chip so do no longer hardship too lots.

2016-10-15 04:05:06 · answer #2 · answered by ? 4 · 0 0

by limiting the applied voltage. A regulator or zenir. Capacitors are not nice to have blowing up. The large cans are quite destructive.

2006-12-17 19:55:56 · answer #3 · answered by Barabas 5 · 0 0

Through testing would be one way. Another is to know the properties of dielectric -- what is its impedence to the flow of current at the thickness in the capacitor?

2006-12-17 19:45:36 · answer #4 · answered by Joe B 3 · 0 0

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